12-(w^2+2w+8)=300

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Solution for 12-(w^2+2w+8)=300 equation: 



12-(w^2+2w+8)=300

We move all terms to the left:

12-(w^2+2w+8)-(300)=0

We add all the numbers together, and all the variables

-(w^2+2w+8)-288=0

We get rid of parentheses

-w^2-2w-8-288=0

We add all the numbers together, and all the variables

-1w^2-2w-296=0

a = -1; b = -2; c = -296;
Δ = b2-4ac
Δ = -22-4·(-1)·(-296)
Δ = -1180
Delta is less than zero, so there is no solution for the equation

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